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对方是一个agent，打开后发现全是加密的，找到加解密函数，如下：

package com.github.catvod.spider.merge;

import java.io.ByteArrayOutputStream;

/* loaded from: classes.dex */
public class cYh {
    private static final String KEY = "gPAQWZ";
    private static final String hexString = "0123456789ABCDEF";

    public static String d(String str) {
        ByteArrayOutputStream baos = new ByteArrayOutputStream(str.length() / 2);
        for (int i = 0; i < str.length(); i += 2) {
            baos.write((hexString.indexOf(str.charAt(i)) << 4) | hexString.indexOf(str.charAt(i + 1)));
        }
        byte[] b = baos.toByteArray();
        int len = b.length;
        int keyLen = KEY.length();
        for (int i2 = 0; i2 < len; i2++) {
            b[i2] = (byte) (b[i2] ^ KEY.charAt(i2 % keyLen));
        }
        return new String(b);
    }
}

转换成python代码如下：

#!/usr/bin/python
# Write Python 3 code in this online editor and run it.
class CYh:
    KEY = "gPAQWZ"
    hex_string = "0123456789ABCDEF"

    @staticmethod
    def d(s):
        b = bytearray()
        for i in range(0, len(s), 2):
            b.append((CYh.hex_string.index(s[i]) << 4) | CYh.hex_string.index(s[i + 1]))
        
        key_len = len(CYh.KEY)
        for i in range(len(b)):
            b[i] ^= ord(CYh.KEY[i % key_len])
        
        return bytes(b).decode('utf-8')

# 解密字符串
encrypted_string = "243F3128062F08242435042E153135343023470B273E2537062407383236036D"
decrypted_string = CYh.d(encrypted_string)
print(decrypted_string)